Chapters

Coordinate Geometry

NCERT Class 10 Mathematics — Chapter 7

Geometry is the right foundation of all painting. — Albrecht Dürer

7.1 Introduction

Points in the plane are given by coordinates (x,y)(x,y). This chapter uses algebra to find distances and dividing points on a line segment.


7.2 Distance Formula

Distance between P(x1,y1)P(x_1,y_1) and Q(x2,y2)Q(x_2,y_2):

PQ=(x2x1)2+(y2y1)2PQ=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance from origin to P(x,y)P(x,y) is x2+y2\sqrt{x^2+y^2}.

Applications: show collinearity, find side lengths of triangles, verify types of triangles.


7.3 Section Formula

Point dividing the join of A(x1,y1)A(x_1,y_1) and B(x2,y2)B(x_2,y_2) in ratio m:nm:n internally:

(mx2+nx1m+n, my2+ny1m+n)\left(\frac{mx_2+nx_1}{m+n},\ \frac{my_2+ny_1}{m+n}\right)

Midpoint (ratio 1:11:1):

(x1+x22, y1+y22)\left(\frac{x_1+x_2}{2},\ \frac{y_1+y_2}{2}\right)


Chapter Summary

  • Distance: (x2x1)2+(y2y1)2\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}
  • Section (internal): (mx2+nx1m+n,my2+ny1m+n)\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)
  • Midpoint: average of coordinates

Exercises (NCERT)

  • Exercise 7.1 — distance formula
  • Exercise 7.2 — section formula, midpoint
  • Miscellaneous Exercise